3.1.67 \(\int x^3 (a+b x) (A+B x) \, dx\)

Optimal. Leaf size=33 \[ \frac {1}{5} x^5 (a B+A b)+\frac {1}{4} a A x^4+\frac {1}{6} b B x^6 \]

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Rubi [A]  time = 0.03, antiderivative size = 33, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, integrand size = 14, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.071, Rules used = {76} \begin {gather*} \frac {1}{5} x^5 (a B+A b)+\frac {1}{4} a A x^4+\frac {1}{6} b B x^6 \end {gather*}

Antiderivative was successfully verified.

[In]

Int[x^3*(a + b*x)*(A + B*x),x]

[Out]

(a*A*x^4)/4 + ((A*b + a*B)*x^5)/5 + (b*B*x^6)/6

Rule 76

Int[((d_.)*(x_))^(n_.)*((a_) + (b_.)*(x_))*((e_) + (f_.)*(x_))^(p_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*
x)*(d*x)^n*(e + f*x)^p, x], x] /; FreeQ[{a, b, d, e, f, n}, x] && IGtQ[p, 0] && (NeQ[n, -1] || EqQ[p, 1]) && N
eQ[b*e + a*f, 0] && ( !IntegerQ[n] || LtQ[9*p + 5*n, 0] || GeQ[n + p + 1, 0] || (GeQ[n + p + 2, 0] && Rational
Q[a, b, d, e, f])) && (NeQ[n + p + 3, 0] || EqQ[p, 1])

Rubi steps

\begin {align*} \int x^3 (a+b x) (A+B x) \, dx &=\int \left (a A x^3+(A b+a B) x^4+b B x^5\right ) \, dx\\ &=\frac {1}{4} a A x^4+\frac {1}{5} (A b+a B) x^5+\frac {1}{6} b B x^6\\ \end {align*}

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Mathematica [A]  time = 0.01, size = 33, normalized size = 1.00 \begin {gather*} \frac {1}{5} x^5 (a B+A b)+\frac {1}{4} a A x^4+\frac {1}{6} b B x^6 \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[x^3*(a + b*x)*(A + B*x),x]

[Out]

(a*A*x^4)/4 + ((A*b + a*B)*x^5)/5 + (b*B*x^6)/6

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IntegrateAlgebraic [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int x^3 (a+b x) (A+B x) \, dx \end {gather*}

Verification is not applicable to the result.

[In]

IntegrateAlgebraic[x^3*(a + b*x)*(A + B*x),x]

[Out]

IntegrateAlgebraic[x^3*(a + b*x)*(A + B*x), x]

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fricas [A]  time = 1.24, size = 29, normalized size = 0.88 \begin {gather*} \frac {1}{6} x^{6} b B + \frac {1}{5} x^{5} a B + \frac {1}{5} x^{5} b A + \frac {1}{4} x^{4} a A \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^3*(b*x+a)*(B*x+A),x, algorithm="fricas")

[Out]

1/6*x^6*b*B + 1/5*x^5*a*B + 1/5*x^5*b*A + 1/4*x^4*a*A

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giac [A]  time = 1.22, size = 29, normalized size = 0.88 \begin {gather*} \frac {1}{6} \, B b x^{6} + \frac {1}{5} \, B a x^{5} + \frac {1}{5} \, A b x^{5} + \frac {1}{4} \, A a x^{4} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^3*(b*x+a)*(B*x+A),x, algorithm="giac")

[Out]

1/6*B*b*x^6 + 1/5*B*a*x^5 + 1/5*A*b*x^5 + 1/4*A*a*x^4

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maple [A]  time = 0.00, size = 28, normalized size = 0.85 \begin {gather*} \frac {B b \,x^{6}}{6}+\frac {A a \,x^{4}}{4}+\frac {\left (A b +B a \right ) x^{5}}{5} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^3*(b*x+a)*(B*x+A),x)

[Out]

1/4*a*A*x^4+1/5*(A*b+B*a)*x^5+1/6*b*B*x^6

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maxima [A]  time = 1.07, size = 27, normalized size = 0.82 \begin {gather*} \frac {1}{6} \, B b x^{6} + \frac {1}{4} \, A a x^{4} + \frac {1}{5} \, {\left (B a + A b\right )} x^{5} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^3*(b*x+a)*(B*x+A),x, algorithm="maxima")

[Out]

1/6*B*b*x^6 + 1/4*A*a*x^4 + 1/5*(B*a + A*b)*x^5

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mupad [B]  time = 0.30, size = 28, normalized size = 0.85 \begin {gather*} \frac {B\,b\,x^6}{6}+\left (\frac {A\,b}{5}+\frac {B\,a}{5}\right )\,x^5+\frac {A\,a\,x^4}{4} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^3*(A + B*x)*(a + b*x),x)

[Out]

x^5*((A*b)/5 + (B*a)/5) + (A*a*x^4)/4 + (B*b*x^6)/6

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sympy [A]  time = 0.07, size = 29, normalized size = 0.88 \begin {gather*} \frac {A a x^{4}}{4} + \frac {B b x^{6}}{6} + x^{5} \left (\frac {A b}{5} + \frac {B a}{5}\right ) \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**3*(b*x+a)*(B*x+A),x)

[Out]

A*a*x**4/4 + B*b*x**6/6 + x**5*(A*b/5 + B*a/5)

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